College Algebra CLEP Prep Practice Exam

Question: 1 / 410

Solve for x in 3x^2 - 15x + 20 = 0

-3, 4

3, 4

To solve this quadratic equation, we can use the quadratic formula. Given the general form of a quadratic equation as ax^2 + bx + c = 0, we substitute the values of a = 3, b = -15, and c = 20 into the formula x = (-b ± √(b^2 - 4ac)) / 2a.

When we simplify this equation, we get two possible solutions for x 3 and 4. However, we need to check the discriminant, which is the value under the square root sign, to see if both solutions are valid.

If the discriminant is negative, we will get complex numbers as solutions, which are not included in the given choices. If the discriminant is positive, we will get two real solutions, like in this case, where the discriminant is equal to

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-4, 3

4, 3

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