College Algebra CLEP Prep Practice Exam

Question: 1 / 410

What is the equation of the line that passes through the points (3,7) and (10,5)?

y = 3x - 2

y = 3x + 2

y = -3x + 2

The equation of a line is typically written in the form y = mx + b, where m is the slope of the line and b is the y-intercept. To find the equation of the line passing through two points, we first need to calculate the slope using the formula (y2 - y1)/(x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.

In this case, using the given points (3,7) and (10,5), we have a slope of (5-7)/(10-3) = -2/7.

From there, we can plug in any of the given points into the equation y = mx + b to find the value of b. Using (3,7), we get 7 = -2/7 * 3 +

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y = -3x - 2

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