College Algebra CLEP Prep Practice Exam

Question: 1 / 410

What is the equation of the circle with center at (2, 5) and a radius of 3?

x2 + y2 = 12

y2 – x2 = 25

x2 + y2 = 9

The equation of a circle is typically written as (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center point and r is the radius. In this case, the center point is given as (2, 5) and the radius is 3.

Option A has the center point (0, 0) and would not result in a circle with a center at (2, 5).

Option B has the center point (0, 0) and would also not result in a circle with a center at (2, 5). Additionally, the values of x and y in the equation are switched, which would result in a hyperbola instead of a circle.

Option D has a minus sign instead of a plus sign between x and y, which would result in an equation for a

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x2 – y2 = 9

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