Question: 1 / 410

What is the inverse of h(x) = 2x + 1?

h−1(x) = (x - 1)2

h−1(x) = x2 -1

h−1(x) = 1/2(x - 1)

The inverse of a function undoes the original function and returns the input value. In this case, the function h(x) multiplies the input by 2 and then adds 1. To undo this, we need to divide by 2 and then subtract 1. This is represented as h^-1(x) = 1/2(x - 1). A and B are incorrect because they do not involve division by 2. D is incorrect because the order of operations is incorrect, it first divides by 2 and then adds 1. This should be reversed to first subtract 1 and then divide by 2, as shown in the correct answer.

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h−1(x) = 1/2x + 1

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