College Algebra CLEP Prep Practice Exam

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Gear up for success on the College Algebra CLEP exam with our comprehensive Prep Practice Exam! Whether you're a math whiz or need a little extra support, our resources are here to help you excel and earn college credit.

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

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What is the equation for a line that passes through the point (3,2) and is perpendicular to the line represented by the equation y = 6x - 8?

y = 6x + 11
y = -6x + 5
y = -6x + 11
y = 6x - 5

The correct answer is: y = -6x + 5

The equation for a line perpendicular to y = 6x - 8 will have a slope that is the negative reciprocal of 6 (-1/6). So, the slope of the line we are looking for is -1/6. Since it passes through the point (3,2), we can use the point-slope form of a line (y - y1 = m(x - x1)) to find the equation. Plugging in the values, we get y - 2 = (-1/6)(x - 3). Simplifying, we get y = (-1/6)x + 5/2. This is equivalent to the equation y = -6x + 5, making option B the correct answer. Options A, C and D all have incorrect slopes and do not pass through the given point.