College Algebra CLEP Prep Practice Exam

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Gear up for success on the College Algebra CLEP exam with our comprehensive Prep Practice Exam! Whether you're a math whiz or need a little extra support, our resources are here to help you excel and earn college credit.

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

What is the equation of a circle if the center is (4,2) and the radius is 3?

(x - 4)2 + (y-2)2 = 9
(x - 4)2 + (y+2)2 = 9
(x + 4)2 + (y-2)2 = 9
(x + 4)2 + (y+2)2 = 9

The correct answer is: (x - 4)2 + (y-2)2 = 9

For a circle with center (h,k) and radius r, the equation is (x-h)^2 + (y-k)^2 = r^2. Since the center of this circle is (4,2) and the radius is 3, the equation becomes (x-4)^2 + (y-2)^2 = 9. Option A is the only one that follows this equation, making it the correct answer. Options B, C, and D all have incorrect signs in front of the y term, which would result in a different circle with a different center point.