College Algebra CLEP Prep Practice Exam

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Gear up for success on the College Algebra CLEP exam with our comprehensive Prep Practice Exam! Whether you're a math whiz or need a little extra support, our resources are here to help you excel and earn college credit.

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What is the equation of the circle with diameter AB, where A is (-3,4) and B is (6,2)?

  1. (x-4.5)2 + (y-3)2 = 4.25

  2. (x+4.5)2 + (y-3)2 = 4.25

  3. (x-4.5)2 + (y+3)2 = 4.25

  4. (x+4.5)2 + (y+3)2 = 4.25

The correct answer is: (x+4.5)2 + (y+3)2 = 4.25

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In this question, the diameter AB has a midpoint at (-3+6)/2 = 3 and (4+2)/2 = 3. Therefore, the center is (3,3). The radius is half of the diameter, which is (6-(-3))/2 = 9/2. So the equation of the circle is (x-3)^2 + (y-3)^2 = (9/2)^2. Simplifying, we get (x+4.5)^2 + (y+3)^2 = 20.25. Option D is the correct equation of the circle. Options A, B, and C are incorrect because they do not

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