College Algebra CLEP Prep Practice Exam

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Gear up for success on the College Algebra CLEP exam with our comprehensive Prep Practice Exam! Whether you're a math whiz or need a little extra support, our resources are here to help you excel and earn college credit.

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

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What is the equation of the circle with the center (-4,7) and the radius 5?

x^2 + y^2 – 10 = 0
(x + 4)^2 + (y – 7)^2 – 25 = 0
(x + 4)^2 + (y – 7)^2 = 5
(x – 4)^2 + (y + 7)^2 = 25

The correct answer is: (x – 4)^2 + (y + 7)^2 = 25

The equation of a circle is given by the equation (x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius. In this case, the center is (-4,7) and the radius is 5, so the correct equation would be (x+4)^2 + (y-7)^2 = 5^2, which simplifies to (x-4)^2 + (y+7)^2 = 25. Option A is incorrect because the radius is not squared. Option B is incorrect because the equation should only contain the squared terms of (x-h) and (y-k), not additional constant terms. Option C is incorrect because the radius should be squared in the equation. Therefore, the correct answer is D.