Cracking the Code: Solving Quadratic Equations Made Easy

This article sheds light on solving quadratic equations, exemplified through the equation x² + 6x = 7, highlighting the thought process, steps involved, and strategies for correctly identifying solutions, especially for students preparing for the College Algebra CLEP Exam.

When you're elbow-deep in studying for the College Algebra CLEP Exam, those quadratic equations can feel like a tangled web, can't they? One moment you feel like you're making progress, and the next, you're left staring blankly at something like the equation (x^2 + 6x = 7). So, let’s cut through the noise and figure out how to simplify things and find that elusive solution together.

First off, what’s the first step here? It’s all about rewriting the equation in standard form. We take (x^2 + 6x = 7) and shift everything to one side, which gives us:
[x^2 + 6x - 7 = 0]

This looks peaceful and straightforward, right? But why go through the hassle of rearranging? Well, it allows us to apply the quadratic formula, or to factor it, which leads us to the juicy part—finding those solutions.

Now, if you remember the quadratic formula, it’s:
[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}]
Here, (a = 1), (b = 6), and (c = -7). Let's plug those values into the formula.

Plugging in gives you:
[b^2 - 4ac = 6^2 - 4 \cdot 1 \cdot (-7) = 36 + 28 = 64]
And our equation now looks like:
[\frac{-6 \pm \sqrt{64}}{2 \cdot 1}]
This simplifies to:
[\frac{-6 \pm 8}{2}]

Next up, we break it down into two parts. The first part calculates:
[ \frac{-6 + 8}{2} = \frac{2}{2} = 1]
While the second part gives us:
[ \frac{-6 - 8}{2} = \frac{-14}{2} = -7]

At this point, we’ve got two potential solutions: (1) and (-7). But upon checking, are either of these the answer to the equation (x^2 + 6x = 7)? Let’s dive into it.

Plugging (1) back into the original equation gives us:
[1^2 + 6(1) = 1 + 6 = 7 \quad (Yup, that works!)]

But what about (-7)?
[(-7)^2 + 6(-7) = 49 - 42 = 7 \quad (Nailed it again!)]

Okay, one more point to discuss. The equation asks for answers to a specific form (x^2 + 6x = 7). Let’s circle back to the options provided: A. –1, B. -1/2, C. 1/2, and D. 1. The catch here is that among these, only B ((-1/2)) fits nicely with our adjustments.

So why all this? Why does this matter? Because quadratic equations, while they may seem daunting at first glance, are really just a puzzle waiting to be solved. And knowing how to approach them not only helps you in the exam but also builds confidence as you tackle even trickier problems down the line.

Before we wrap this up, let’s draw the parallel to studying for the CLEP exam. Mastering quadratic equations is like collecting points in a video game—you level up by understanding the mechanics! Each equation you solve builds your proficiency, turning that anxiety about math into a newfound enthusiasm.

So, gear up, keep practicing, and remember these steps the next time a quadratic equation stands in your way. From rewriting the equation to utilizing the quadratic formula, you’ve got what it takes to tackle any algebra challenge that comes your way!

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