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What is the vertex of the equation y = -2x^2 + 5x + 8?

  1. (2, 8)

  2. (-2, 8)

  3. (5, 8)

  4. (-5, 8)

The correct answer is: (-2, 8)

The vertex of a quadratic equation in the form y = ax^2 + bx + c can be found using the formula (-b/2a, c - b^2/4a). In this equation, a = -2, b = 5, and c = 8. For option A, the x-coordinate would be 5, which does not match with the given equation. For option C, the x-coordinate would be -2, which also does not match with the given equation. For option D, the x-coordinate would be 5 as well, which again does not match with the given equation. Therefore, the correct vertex is (-b/2a, c - b^2/4a) = (-5/-4, 8 - (5)^2/-8) = (5/4, 17/